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He looks great but has really not done anything to justify huge money yet. He isn't in a league of his own, is the potential just there or is there something I am missing? I want us to sign the guy but I'd like to be sold first, please.
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
His numbers are pretty consistent for the #3 WR.... he is also pretty durable, and he fills a need of a bigger WR the Bills need
give him more opportunities and he should be able to improve on his already consistent #'s
but that is opinion based on stats
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
It's simple. He's bigger, more physical, and can catch. Basically, he's not Josh Reed.Originally posted by Skooby"The government's view of the economy could be summed up in a few short phrases: If it moves, tax it. If it keeps moving, regulate it. And if it stops moving, subsidize it."
Ronald Reagan
40th president of US (1911 - 2004)
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
Exactly Skoob. Buffalo needs to stick to their offer and not up it just b'cse he's trying to use the Redskins as leverage to get more money. If they want to overpay for him, then let them go ahead...Comment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
boldin and fitz are both better than evans too. So what does that say about that ******ed comparison.Comment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
He has had several injuries and missed games, is that durable? Hamstring injury? Shoulder injury? quadriceps?Originally posted by ddarylComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
give him no. 3 money with incentives that would pay him a no. 2 if he lives up to it.Comment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
two probowl recievers ahead of him for one
im not sold on him either but there have been other number three guys to go on to be pretty good number twosOne set of rules for all in the beloved communityComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
We only have 15 other Johnson threads this could of gone into...COMING SOON...
Originally posted by Dr.LecterComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
Several injuries?Originally posted by Skooby
He has missed 3 games in entire career. (2 in '05 and 1 in '03)
He might not be the answer, but he is durable.Originally posted by mysticsotoComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
None spoke of injury, just concerns of losing him. I am asking what he has done to earn big money?Originally posted by DraftBoyComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
Originally posted by Skooby
He really hasn't earned "Big Money" he'll get a significant raise but I don't see him getting #1 WR money
He'll probably get an incentive laden contract that will pay him big if he performs big.
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
He's looking for huge money, not like $2M a year but more like $5-6 M a year. That is the way I understood it anyways.Originally posted by ddarylComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
it says he should have produced more. between boldin and fitz getting hurt, johnson has been on the field as a starter 16 times in the last two years but only boldin and fitz produce.. not johnson.Originally posted by RingofFire
he is a solid number 3. nothing else. pay him starters money and your just going to be disappointed."All hockey players are bilingual. They know English and profanity." ~ Gordie HoweComment
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Re: Bryant's a #3 on his team that loses every year, so what makes him #2 here
Originally posted by Skooby
Who cares what he is looking for....
It's what he'll get.....
I seriously doubt the Bills are going to offer him 5-6 million a season..
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